Scott-T Connection of Transformer

Electrical Technology

What is Scott Connection or Scott-T Transformer?

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Scot Connection

Scott connection is a type of connection of transformer that used to get two-phase power supply from three-phase source or vice-versa. The Scott connection is also known as Scott-T Transformer. This method of transformer connection was invented by Charles F. Scott. So, after his name, this method is widely known as the Scott connection.

Related Post: Open Delta Connections of Transformers

Connection Diagram of Scott’s-T Connection

In Scott connection, two single-phase transformers are electrically connected but magnetically separated. One transformer is known as the main transformer and the second transformer is known as an auxiliary transformer. The auxiliary transformer is also termed a teaser transformer. The connection diagram of Scott’s connection is as shown in the figure below.

The primary winding of the main transformer is center-tapped at point D. And the two lines (Y and B) of a three-phase supply are connected to the primary winding of the main transformer. And the secondary winding of the main transformer is connected across points a1 and a2.

The primary winding of an auxiliary transformer is connected between the center-tapped point D and the remaining line terminal (phase R). And the secondary winding of an auxiliary transformer is connected between points b₁ and b₂.

The primary winding of the main transformer is center-tapped at equal parts. Therefore, the number of turns in part YD and BD is the same.

Phasor Diagram of Scott Transformer

The line voltages of a three-phase supply (V_RY, V_YB, and V_BR) are equal in magnitude and 120-degree apart. The phasor diagram of supply voltage is shown in the figure below.

The phasor diagram of a three-phase supply can be drawn as an equivalent triangle. The magnitude of all line voltage is the same. Therefore,

V_RY = V_YB = V_BR = V_L

For calculation, we consider phasor YB as a reference phasor.

V_YB = V_L∠ + 0°

V_RY = V_L∠ + 120°

V_BR = V_L∠ – 120°

The center tapping point D divides primary winding into equal parts. Consider, the number of turns in the primary winding is N_P. Therefore,

So, the voltage in portion YD and BD is the same and in phase with voltage V_YB.

Now, we need to find the voltage of the primary winding of a teaser transformer (V_RD). From the phasor diagram, we can write;

V_RD = V_RY + V_YD

V_RD = 0.866 V_L ∠90°

The voltage given to the primary winding of a teaser transformer is 0.866 times of the main transformer. The voltage across a secondary winding of teaser transformer is V_2T and the voltage across a secondary winding of the main transformer is V_2M. Now, V_RD is applied to the primary winding of a teaser transformer. Hence, the V_2T leads V_2M by 90˚. And the magnitude of both voltages is the same. The phasor diagram of Scott’s connection is shown in the figure below.

The voltage per turn must be the same in winding to create the same flux. Therefore, to make voltage per turn in a primary winding of the main and teaser transformer, the number of turns in a primary winding of the teaser transformer must be;

Therefore, the turns ratio in the teaser transformer is;

Hence, the secondary windings of each transformer have the same voltage magnitude with a 90˚ phase difference. So, it creates a balanced two-phase system.

Position of Neutral Point N

If the neutral point is available in a three-phase supply, tapping is provided on the primary teaser transformer. For example, taping is available at point N. Hence, the voltage across terminals RN is;

In the above equations, we have derived the value of the voltage between RD;

The voltage across point ND is;

So, we have voltage across points RN, RD, and ND. For the same voltage turn ratio in these windings, the number of turns are chosen as;

From the above equation, we can derive the ratio of neutral point N divides the primary winding of teaser transformer as; RN:ND = 2:1.

Relationship of Input and Output Currents

The line current of the input three-phase supply is I_R, I_Y, and I_B. Here, we use two transformers and both transformers have primary and secondary winding. So, the current passes through the primary and secondary winding of the main and teaser transformer are as listed below.

I_1M = Primary current of the main transformer
I_2M = Secondary current of the main transformer
I_1T = Primary current of teaser transformer
I_2T = Secondary current of teaser transformer

From the connection diagram, the current that passes through the primary winding of the teaser transformer is line current IR. Therefore,

I₁_T = I_R

The secondary winding of both transformers is identical. Hence, the magnitude of current that passes through both secondary winding is the same.

| I₂_M |= | I₂_T |

The balance MMF equation of teaser transformer is (neglecting effect of magnetizing current);

I₁_T N_RD = I₂_T N_S

I_R = 1.15 K I₂_T = I₁_T

Now, the balance MMF equation for the main transformer is;

I₁_M N_YD – I₁_M N_BD = I₂_M N_S

I_Y – I_B = 2 K I₂_M

For balanced three-phase system;

I_R + I_Y + I_B = 0

I_B = – I_R – I_Y

I_Y – (- I_R – I_Y = 2 K I₂_M

I_Y + I_R + I_Y = 2 K I₂_M

I_R + 2I_Y = 2 K I₂_M

Now, put the value of current I_Y into the equation of I_B;

These equations of current are valid for balanced and unbalanced loads.

Applications of Scott Connection

The applications of Scott connection are listed below.

This type of connection is used to connect a three-phase system with a two-phase system. And the power can be flow in both directions.
The Scott connection is used to supply single-phase load (like electric trains) from a balanced three-phase supply.
When the power is drawn from a three-phase supply, it is covert into a single-phase supply that uses for single-phase electric furnaces.